Hi Alex
---
State-changes are recorded in ticket_history with
writing in
ticket_history.names '%%prev_state%new_state%%'.
You just
query for '%closed successful%', so you also receive all
tickets with
prev_state = 'closed sucessful'. Correct would be
'%\%\%closed sucessful\%'
(if '%' is masked within SQL as '\%' - I don't
know).
---
Yes, I know, but since I filtered only closed
tickets (WHERE t.ticket_state_id=2), it's not necessary cause the last
state_change is surely the ticket closing.
However you are right, a more accurate clause
would be the following
... AND th.name LIKE '\%\%%\%\%closed
successful%'
---
> This is still not a perfect
measurement of time spent to close the
> ticket, but is good enough for
my purposes at the moment. Let's say that
> a ticket is closed, then
reopened, then closed again: then I'm not able
> to calculate the time
the ticket remained closed the first time. To do
> this, I think I need
to use some programming language (like PHP or
> Perl), and maybe I'll do
it later.
You can write a Static-stats-OTRS-module for
this.
---
I know, but I don't know anything about Perl!!! :P
Bye
Gabriele
----- Original Message -----
To: "User questions and discussions about
OTRS.org" <otrs@otrs.org>
Sent: Wednesday, June 20, 2007 8:31
AM
Subject: Re: [otrs] Trying to find out the time
taken to close a ticket
Hi Gabriele,
Gabriele D'Andrea schrieb:
> Well,
>
there was something I still didn't understand about OTRS DataBase
Schema.
> Now finally I got it.
> I've written a SQL query, that
allow me to filter closed tickets, and
> see the time taken from ticket
opening till the last closing.
>
> SELECT t.tn,
t.customer_id, t.create_time, MAX(th.change_time) AS
> change_time,
DATEDIFF(MAX(th.change_time), t.create_time) AS open_days,
>
TIMEDIFF(MAX(th.change_time), t.create_time) AS open_time
> FROM ticket AS
t JOIN ticket_history AS th ON t.id=th.ticket_id JOIN
>
ticket_history_type AS tht ON th.history_type_id=tht.id
> WHERE
t.ticket_state_id=2 AND tht.id=27 AND th.name LIKE '%closed
>
successful%'
> AND t.customer_id LIKE '%'
> GROUP BY
t.id;
I didn't check you query extensive, but I think
it's not complete correct.
State-changes are recorded in ticket_history with
writing in
ticket_history.names '%%prev_state%new_state%%'.
You just
query for '%closed successful%', so you also receive all
tickets with
prev_state = 'closed sucessful'. Correct would be
'%\%\%closed sucessful\%'
(if '%' is masked within SQL as '\%' - I don't
know).
>
> This lead to the following
output
>
> *tn* *customer_id* *create_time*
*change_time* *open_days* *open_time*
> 2007051510000075
ecohmedia 2007-05-15 12:10:06 2007-05-15
> 12:18:28
0 00:08:22
> 2007051510000084 ecohmedia 2007-05-15
12:40:08 2007-05-15
> 14:46:34 0 02:06:26
>
2007051510000137 ecohmedia 2007-05-15 16:39:45 2007-05-15
> 16:44:13 0 00:04:28
> 2007051610000055
2007-05-16 11:22:09 2007-05-17 10:41:13 1
23:19:04
> 2007051710000044 2007-05-17 16:23:34
2007-05-17 16:24:08 0 00:00:34
> 2007051810000079
FATER 2007-05-18 14:48:07 2007-05-18 15:35:58 0
>
00:47:51
> 2007051810000122 FATER 2007-05-18 16:03:57
2007-06-19 17:55:30 32
> 769:51:33
> 2007061810000013
SANOFI 2007-06-18 09:41:25 2007-06-18 10:07:41 0
> 00:26:16
>
>
>
> This is still
not a perfect measurement of time spent to close the
> ticket, but is
good enough for my purposes at the moment. Let's say that
> a ticket is
closed, then reopened, then closed again: then I'm not able
> to
calculate the time the ticket remained closed the first time. To do
>
this, I think I need to use some programming language (like PHP or
>
Perl), and maybe I'll do it later.
You can write a Static-stats-OTRS-module for
this.
> Then the output format is not perfect
too, cause days are integer (and
> that colud be fine), but time is in
hh:mm:ss (should be good to have
> days hh:mm:ss for longer periods),
thus data may need some further
> manipulation.
>
> In
the end I wish to thank all the people in this community that give me
>
feedbacks and precious informations, expecially Alexander Scholler
>
Further comments, advices, warnings are also appreciated.
No problem.
>
> Gabriele
D'Andrea
Bye, Alex
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